On Wed, 4 Oct 2000, Roland Bramm wrote:
> Char_t *Names[20][80];
>
> Names[1][] = "The Filled Text"; // Sometimes this is filled more than
I'm not sure about the meaning of such a line.
Names is a ***char,
so each Names[i][j] is a *char.
I would understand Names[i][j] = "const string";
And then :
cout << Names[i][j];
But here, for me you're filling char* cells with chars.
If I follow you, I would have wrote either :
Char_t Names[20][80]; // allocation of a static array of chars
for (int i=0;i<20;i++)
sprintf(Names[i],"The Filled Text %d",i);
strcpy(Name[1],"ANOTHER TEXT");
for(int j = 0; j<20;j++){
cout << Names[j] << endl;
}
Or :
Char_t *Names[20]; // allocation of an array of char pointers
for (int i=0;i<20;i++)
{
char *prv=new char[80];
sprintf(prv,"The Filled Text %d",i);
Names[i]=prv;
}
delete Names[1];
Names[1]="ANOTHER TEXT";
for(int j = 0; j<20;j++){
cout << Names[j] << endl;
}
Hope it helps,
Yannick
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