Hi Deng,
----- Original Message -----
From: Huaizhang Deng <deng@bnl.gov>
To: <roottalk@pcroot.cern.ch>
Sent: Monday, June 05, 2000 7:55 PM
Subject: [ROOT] function can not be compiled
> I wrote the following program.
>
> Double_t RatioFunc(Double_t *t, Double_t *par) {
> Double_t R;
> R=par[0]*cos(2*3.14159265*0.0002291*(1-par[1]*1.0e-6)*t[0]+par[2])+par[3];
> return R;
> }
>
> TF1* RatioFit(TH1F* h, Float_t t_start, Float_t t_end) {
>
> TF1 *RatioFit=new TF1("RatioFit", RatioFunc, 0, 700000, 4);
>
> RatioFit->SetParNames("A", "R", "'f#", "offset");
> RatioFit->SetRange(t_start, t_end);
> RatioFit->SetParameters(0.4, 120, 0, 0);
>
> h->Fit("RatioFit", "R");
> return RatioFit;
> }
>
> Then I tried to do
>
> int i;
> TF1* fit;
> for(i=0; i<5; i++) fit=RatioFit(hist, t, 400000.);
|
|---> why there is one more '0' than the following ? If "overflow" is not the reason. The initialization of 'fit' could be another possibility. I am not a root expert but I had similar problem with (char *) handle on AIX machine. Hope it can help you.
Cheers Wen Mei
>
> After the first fit, which is o.k., it complain "Function:RatioFit cannot be
> compiled".
> However, the following program works well.
>
> int i;
> TF* fit;
> fit=RatioFit(h, t, 40000);
> for(i=1; i<5; i++) fit=RatioFit(hist, t, 40000);
>
> I wonder why those two programs make difference.
>
> Huaizhang Deng
>
>
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